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Propulsion of a vehicle in a tube

Sequence 22
F-16 and which are not. The flow behind the vehicle. Because of the boundary condition y+oo = 0, the only possible flows…
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F-17 Where y <0, the "_" sign applies in Eq. 16 but the flow is stable only if dy ~O. Therefore, the…
Sequence 24
F-18 The only physical meaning that can be attributed to the "unstable wakes" is that they cannot exist except as…
Sequence 25
F-19 where q3-4 is the heat received by the unit mass of the fluid between the two stations: Equs. 7 and 9 may be re-written…
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F-20 one obtains I /-!/3 or When Y4 = 0 (i.e., when Mo is below the critical value for stability of the wake), P3 = P4 =…
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F-2l various means and under various conditions. Power required. The following calculations concern only the power required…
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F-22 transfer of energy to the flow is assumed to take place in every case between stations 1 and 3. Thus, p. = rn C!e (130…
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F-23 With external propulsion, the relative flow is iso- energetic from station 1 to station 3. Assuming the flow to be…
Sequence 30
F-24 The large loss of stagnation pressure is due primarily to a shock between stations t and 2. For the condition of…
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Finally, F-25 = --.t. 7,;~ 7;0 =. 638 r-/ Thus, the ratio between the power required with this mode of internal propulsion…
Sequence 32
F-26 steady motion of the vehicle. The results are plotted, for the condition under consideration, in Fig. 3. Values of Yl…
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F-27 For the case of internal propulsion, the condition F3 = Fl and Eqs. 15, 17, and 24 yield Ml = .621, T 0 3 = 1.1745 To…
Sequence 34
F-28 Dl = .475 (Dl) = .275, hence Ml = .Z89 and Nl = .2609. Then Eq. 15 yields Fl/PoA = 14.39. Assuming P2 o / Pl o = .95,…
Sequence 35
F-29 is used to energize the flow between 1 aud t, the disturbances ahead of 1 can be "swallowed". Then the flow at…
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F-30 whence ;% = 2.320 Af = ,39/7 Therefore 3 T2 o /To o = (.3917/.3846)2 = 7:~ 7:6 = iO -2.25 = 2.334 1.03 73, and…
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F-31 These waves will not affect the power required. If the mode of propulsion is of the ramjet type, the required power…
Sequence 38
F-32 and whence M2 = 2.223 and T20/Too = 1.0601. there follows T2 o /To = 2.385 and o Then, since To ITo = 2.25, /) - I…
Sequence 39
F-33 stagnation pressure) and to re-accelerate the flow to supersonic speed through a converging-diverging passage downstream…
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F-34 controlled by the downstream boundary conditions. The calculation of the power factor is particularly simple with this…
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F-35 are largely determined by the mode of propulsion. The same can be said, of course, of the attendant flow losses and of…
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F-36 the direction of the acceleration of the vehicle or in the opposite direction, depending on the speed of the vehicle and…
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F-37 that there is a range of operating regimes within which the bound- ary conditions demand that the wake flow be…
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F-38 addition to· the flow, promise attractive advantages of economy and mechanical simplicity. These modes also lend…
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F-39 References 1. To11mien, W., "Luftwiderstand und Druckver1auf bei der Fahrt von ZUgen in einem Tunnel, II. '…
Sequence 46
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