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Analysis of the effects of wall perforations on the performance of a vehicle in a tube
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4. 5. 6. 3.2. Dra.g Disc in a Perforated-Wall Tube 3.2.1. Experimental Facility 3.2.2. Test Procedure 3.2.3. Data…
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Figure Number 11 LIST OF FIGURES Title Page Wall-Fixed and Disc Fixed Frames of Reference 51 Typical Pressure and…
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Figure Number 16b 17 18 19 20 21 22 23 24 25 26 27 28 29 Title Drag Disc Alone - Stationary Wall Pressure as…
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ABSTRACT The flow induced by a vehicle traveling through a porous- wall tube is analyzed as a one-dimensional incompressible…
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D dm w f n p p Q q r u u u s u w v w NOMENCLATURE hole area per unit length of tube contraction coefficient…
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1 1. INTRODUCTION This report deals with the effects of wall perforations on the propulsion of a vehicle traveling through a…
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2 condition derived in terms of a potential flow. This boundary condition is based on the linerized Bernoulli equation giving…
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3 propelled or wheel driven vehicle generates a flow in the direction of the motion of the vehicle because of the region of…
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4 For steady level motion, the drag disc solution must be matched to the actuator disc solution with the correct amount of…
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2. THEORETICAL ANALYSIS 2.1 Equations of Motion The one-dimensional steady-flow momentum and continuity equations for the…
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6 boundary conditions are established the resulting integrated equations define the entire inviscid flow field. In the case…
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In the wake of the vehicle, however, the magnitude of the inviscid flow velocity depends on the mode of propulsion and must be…
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8 x o --r.. 2.6 Equations 2.4 and 2.5 discribe the inviscid flow pressure and velocity distribution ahead of the drag disc…
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flow to change is a pressure difference across the wall. At station 3, P = P since the pressure must return to atmospheric due…
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It should be noted that if Pa~ P 2 " outflow occurs and eq. 2.1 becomes dP = -2U dU 10 2.10 Outflow results in a…
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11 Ud ~ .5. The momentum equation written between 2 and 2' is, for Ud ~ .5 and P2 , = Pa since the velocity at 2 is u…
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Equations 2.4, 2.11, 2.12 and 2.15 combined can be solved for U d in terms of ;8 to get i f = ~ [-f3 + ~2-3f3 + l·S ] d (.…
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13 a given disc porosity )9, until the pressure difference (P1-P2 ,) across the disc is determined. For viscous flow, this…
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that, upon numerical integration, the boundary condition of P - P = 0 a and U = 1 can be satisfied. 2.2.2.2. X» 0 -- INFLOW…
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Numerical solutions to eqs. 2.1 and 2.2 for inflow behind the drag disc can be obtained by assuming a value of P 2 , - P a…
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16 2.21 where the constant of integration has been evaluated at some distance ahead of the disc where P = P and the velocity…
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17 2.3.1.2. X~ 0 -- OUTFLOW. The inviscid one-dimen- sional momentum equation for outflow dP = -2UdU 2.25 shows dP/dU to…
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18 2.3.2. Viscous Flow 2.3.2.1. X ~ 0 -- INFLOW. For U 2!: 1, the friction term is negative, i.e. the flow is moving faster…
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+ C-r r 2.. c x L 4 2. 2.28 In eqs. 2.27 and 2.28, the first terms represent the change in momentum 19 for inviscid flow.…
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2.3.2.3. Thrust. The thrust coefficient for the actuator disc with viscous flow is given by = 2.4. The Vehicle as Matched…
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